The length of an organ pipe open at both ends is \(1m\). What would be the fundamental frequency of the pipe, if the velocity of the sound in air is \(340\frac{m}{s}\)? If one end of the pipe is closed, then what will be the fundamental frequency?
Ans: \(\nu=85Hz\) .
Find: the ratio of length of a closed pipe to that of an open pipe in order that the second overtone of the former is in unison with fourth overtone of the later?
Ans: \(\frac{L}{L’}=\frac{1}{2}\).
An open pipe is suddenly closed at one end with the result that the frequency of the third harmonic of the closed pipe is found to be higher by \(100Hz\) than the fundamental frequency of open pipe. What is the fundamental frequency of the open pipe?
Ans: \(\nu_{o}=200Hz\).
The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If the length of the open pipe is \(60cm\), What is the length of the closed organ pipe?
Ans: \(L_{1}=15cm\).
A pipe \(30cm\) long is open at both ends. Which harmonic mode of the pipe is resonantly excited by a \(1.1KHz\) source? Will resonance with the same sources be observed if one end of the pipe is closed ? Take: The speed of sound in air as \(330\frac{m}{s}\).
Ans: \(2^{nd}Harmonics\) and \(No\).
Two open organ pipes played together produces beats at the rate of three beats per second. Find: Their frequency if one of the pipe is\(33cm\) long and the other is \(33.5cm\) long.
Ans: \(\nu_{1}=201Hz\) and \(\nu_{2}=198Hz\).
A resonance tube is resonated with a tuning fork of frequency \(512Hz\). Two successive lengths of the resonated air column are \(16.0cm\) and \(51.0cm\). The experiment is performed at the room temperature of \(40^{o}C\). Calculate: The speed of sound at \(0^{o}C\) and end correction.
Ans: \(334\frac{m}{s}\) and \(1.5cm\).
A steel rod of length \(1m\) is clamped at its middle. The rod is made to vibrate such that the fundamental frequency of the longitudinal waves of the rod is \(2.0KHz\). Find: The speed of the sound in steel?
