An electric dipole consists of two charges \(+20\mu C\) and \(-20\mu C\) separated by a distance of \(1cm\). Calculate: the electric field intensity at any point on the axial line at a distance of \(10cm\) from the mid point of the dipole.
Two charges each of \(1\mu C\) but opposite sign are \(0.1m\) apart. Calculate: the electric field at a point situated at a distance of \(12cm\) from the mid point of the dipole along the equilateral direction.
What is the magnitude of the electric field intensity due to a dipole of dipole moment \(\left(2\times10^{-8}\right)Cm\) at a point situated at a distance of \(1m\) from the center of the dipole, when the line joining the point to the center of the dipole makes an angle of \(60^{o}\) with the dipole axis?
Ans: \(E=238.1\frac{N}{C}\).
Calculate: the electric field intensity due to an electric dipole of length \(10cm\) and consisting of two charges \(\pm2\mu C\) at a distance of \(50cm\) from each charge.
A system of two charges \(q_{A}=\left(2.5\times10^{-7}\right)C\) and \(q_{B}=-\left(2.5\times10^{-7}\right)C\). located at points \(A\left(0,0,-15\right)cm\). and \(B\left(0,0,+15\right)cm\) respectively. Find: the total charge and the electric dipole moment of the system?
Ans: \(Q_{net}=0\left(Zero\right)\) and \(p=\left(7.5\times10^{-8}\right)Cm\).
The electric field due to a short dipole at a distance \(r\), on the axial line, from its mid point is the same as electric field at a distance \(r’\) on its equilateral line from its mid point. Determine: \(\frac{r}{r’}\).
Ans: \(\frac{r}{r’}=\frac{2^{\frac{1}{3}}}{1}\).
The force experienced by a unit charge when placed at a distance of \(0.01m\) from the middle of an dipole on its axial liane is \(0.025N\) and when it is placed at a distance of \(0.2m\), the force is reduced to \(002N\). Calculate: the dipole length.
Ans: \(2a=0.10m\).
An electric dipole consists of two charges of \(\left(+16\times10^{-19}\right)C\) and \(-\left(16\times10^{-19}\right)C\) separated by a distance of \(\left(3.9\times10^{-12}\right)m\). The dipole is placed in a uniform electric field of \(10^{5}\frac{N}{C}\). Calculate: (a) The electric dipole moment? (b) Potential energy of the dipole in stable equilibrium?
Ans:(a) \(p=\left(6.24\times10^{-30}\right)Cm\) and (b) \(-\left(6.24\times10^{-25}\right)J\).
A molecule of a substance has permanent electric dipole moment equal to \(10^{-29}Cm\). A mole of this substance is polarized (at low temperature) by applying a very strong electric field of magnitude \(10^{6}\frac{V}{m}\). The direction of electric field suddenly changed by an angle of \(60^{o}\). estimate the heat released by the the substance in aligning its dipoles along the new direction of the field. fir simplicity, assume \(100\%\) polarization of the sample.
